re = /\b(?!(?:888|999))\d+\b/
str = '88839182 (not valid)
99923213 (not valid)
98188823 (valid)
98939117'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html