const regex = /(?:^(?:[(]?\b(?:_xTagsx_)\b(?:and|[ ,.&+/-])*)+[:. \)-]*|(?:[:. \(-]|in|with|using)*(?:\b(?:_xTagsx_)\b(?:and|[ ,&+/)-])*)+([?.! ]*)$)/gim;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('(?:^(?:[(]?\\b(?:_xTagsx_)\\b(?:and|[ ,.&+\/-])*)+[:. \\)-]*|(?:[:. \\(-]|in|with|using)*(?:\\b(?:_xTagsx_)\\b(?:and|[ ,&+\/)-])*)+([?.! ]*)$)', 'gim')
const str = `Note use of _xTagsx_ placeholder; this is replaced in code.
Be careful: any escaped characters will require double-escape in string to form regexp.
** Flags should be gi in production; 'm' for test here only.
Remove leading tags from:
_xTagsx_ & _xTagsx_: Rest of title
_xTagsx_ - _xTagsx_ - _xTagsx_ - Rest of title
_xTagsx_ Rest of title
_xTagsx_, _xTagsx_ & _xTagsx_ Rest of title
_xTagsx_. Checking if string contains text from an array of substrings.
_xTagsx_ and _xTagsx_:
_xTagsx_ - Rest of title
_xTagsx_/_xTagsx_ - Rest of title
(_xTagsx_) Rest of title
Remove Trailing tags (but leave final punctuation, if any) from:
How to use <= in _xTagsx_ _xTagsx_?
Rest of title (_xTagsx_)
Rest of title (_xTagsx_/_xTagsx_ - _xTagsx_)
Rest of title - in _xTagsx_.
Leave alone:
Use of _xTagsx_ in general.
_xTagsx_as part of a word_xTagsx_`;
const subst = `$1`;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions