const regex = /(?:^(?:[([]?(?:_xTagsx_)(?!\.\w)(?:and|[ ,.&+/-])*)+[:. \)\]-]*|\b(?:(?:[:. \(\[-]|in|with|using|by|for)*(?:(?:_xTagsx_)(?:and|[ ,&+/)\]-])*)*)+([?.! ]*)$)/gim;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('(?:^(?:[([]?(?:_xTagsx_)(?!\\.\\w)(?:and|[ ,.&+\/-])*)+[:. \\)\\]-]*|\\b(?:(?:[:. \\(\\[-]|in|with|using|by|for)*(?:(?:_xTagsx_)(?:and|[ ,&+\/)\\]-])*)*)+([?.! ]*)$)', 'gim')
const str = `Note use of _xTagsx_ placeholder; this is replaced in code.
Be careful: any escaped characters will require double-escape in string to form regexp.
** Flags should be gi in production; 'm' for test here only.
Remove leading tags from:
_xTagsx_ & _xTagsx_: Rest of title
_xTagsx_ - _xTagsx_ - _xTagsx_ - Rest of title
_xTagsx_ Rest of title
_xTagsx_, _xTagsx_ & _xTagsx_ Rest of title
_xTagsx_. Checking if string contains text from an array of substrings.
_xTagsx_ and _xTagsx_:
_xTagsx_ - Rest of title
_xTagsx_/_xTagsx_ - Rest of title
(_xTagsx_) Rest of title
[_xTagsx_][_xTagsx_] Rest of title
Remove Trailing tags (but leave final punctuation, if any) from:
How to use <= in _xTagsx_ _xTagsx_?
Rest of title (_xTagsx_)
Rest of title [_xTagsx_][_xTagsx_]
Rest of title (_xTagsx_/_xTagsx_ - _xTagsx_)
Rest of title - in _xTagsx_.
Rest of title by _xTagsx_?
Rest of title for _xTagsx_!
Rest of title with _xTagsx_?
Leave alone:
Use of _xTagsx_ in general.
Rest of title Kremlin _xTagsx_.
_xTagsx_.io.InvalidClassException
`;
const subst = `$1`;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions