import Foundation
let pattern = #"^(?:[A-Z]|[A-Z][A-Z]|[A-X][A-F][A-D])(?:[1-9]|[1-9][0-9]|[1-9][0-9][0-9]|[1-9][0-9][0-9][0-9]|[1-9][0-9][0-9][0-9][0-9]|[1-9][0-9][0-9][0-9][0-9][0-9]|10[0-3][0-9][0-9][0-9][0-9]|104[0-7][0-9][0-9][0-9]|1048[0-4][0-9][0-9]|10485[0-6][0-9]|104857[0-6])$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
A1
AA11
AAA111
ZZ12
YY1048575
XFD1048576
A0
AA01
AAZ1111111
XFE1048576
XFD1048577
ZZZ333
ZZZ9999999
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression