import Foundation
let pattern = #"\b(\(?0?\d{2}\)?)?\s?9[\s\-]?\d{4}[\s\-]?\d{4}\b"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
---> DEVE ENCONTRAR:
11991234567
011991234567
119111111111 <- Tem certeza que deve encontrar? tem 11 (DDD) e depois tem 10 dígitos
11 99123 4567
011 99123 4567
11 9 9123 4567
011 9 9123 4567
---> DEVE ENCONTRAR (EXEMPLOS DA PERGUNTA + ALGUMAS EXTENSÕES):
993345987
9 93345987
(21)932324343
(021)932324343
(21)9 3232 4343
(021)9 3232 4343
(21) 9 3232 4343
(021) 9 3232 4343
NÃO DEVE ENCONTRAR:
11 99123 45671
111 99123 4567
011 99123 45678
811 99123 45678
a9999999999999999999989999123
118111111111
123456789123456789
33933333333333333333
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression