import Foundation
let pattern = ##"""
(?x) # free-spacing mode
(?(DEFINE)
# decimal to decimal: 1.2% to 21.53%
(?<dec_to_dec>
(?:[0-9]{1,3}[\,\.][0-9]{1,3}[\%]\sto\s[0-9]{1,3}[\,\.][0-9]{1,3}[\%])
)
# Decimal to Whole number: 1.2% to 21%
(?<dec_to_int>
(?:[0-9]{1,3}[\,\.][0-9]{1,3}[\%]\sto\s[0-9]{1,3}[\%])
)
# Whole number to Decimal: 1% to 21.53%
(?<int_to_dec>
(?:[0-9]{1,3}[\%]\sto\s[0-9]{1,3}[\,\.][0-9]{1,3}[\%])
)
# Whole number to whole number: 1% to 21%
(?<int_to_int>
(?:[0-9]{1,3}[\%]\sto\s[0-9]{1,3}[\%])
)
# Single Whole Number: 21%
(?<single_int>
(?:[0-9]{1,3}[\%])
)
# Single Whole Number: 21%
(?<single_dec>
(?:[0-9]{1,3}[\,\.][0-9]{1,3}[\%])
)
)
(?&dec_to_dec)|(?&dec_to_int)|(?&int_to_dec)|(?&int_to_int)|(?&single_int)|(?&single_dec)
"""##
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"France: 2.8% to 21%"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression