const regex = /((([A-Za-z]{3,9}:(?:\/\/)?)(?:[-;:&=\+\$,\w]+@)?[A-Za-z0-9.-]+|(?:www.|[-;:&=\+\$,\w]+@)[A-Za-z0-9.-]+)((?:\/[\+~%\/.\w-_]*)?\??(?:[-\+=&;%@.\w_]*)#?(?:[.\!\/\\w]*))?)/ig;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('((([A-Za-z]{3,9}:(?:\\\/\\\/)?)(?:[-;:&=\\+\\$,\\w]+@)?[A-Za-z0-9.-]+|(?:www.|[-;:&=\\+\\$,\\w]+@)[A-Za-z0-9.-]+)((?:\\\/[\\+~%\\\/.\\w-_]*)?\\??(?:[-\\+=&;%@.\\w_]*)#?(?:[.\\!\\\/\\\\w]*))?)', 'ig')
const str = `Good Day,I would like to \$1000 (for example remove these parenthesis) \$test \$ asdf [and remove these brackets] inquire the price of the 3D product name here. Currently we have the other product name here which I believe has an accuracy of about 0.0005 199 200. http://www.example.com this is a test`;
const subst = ``;
// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);
console.log('Substitution result: ', result);
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions