re = /(.)\n(\S)/m
str = 'Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.
Dictum sit amet justo donec enim diam vulputate.
Nunc faucibus a pellentesque sit amet.
Quis enim lobortis scelerisque fermentum dui faucibus in.
Leo duis ut diam quam nulla porttitor massa id neque.
Vitae tortor condimentum lacinia quis vel eros.'
subst = '\\1 \\2'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html