import Foundation
let pattern = #"\b(?:a(?:ndroid|vantgo)|b(?:lackberry|olt|o?ost)|cricket|docomo|hiptop|i(?:emobile|p[ao]d)|kitkat|m(?:ini|obi)|palm|(?:i|smart|windows )phone|symbian|up\.(?:browser|link)|tablet(?: browser| pc)|(?:hp-|rim |sony )tablet|w(?:ebos|indows ce|os))"#
let regex = try! NSRegularExpression(pattern: pattern, options: .caseInsensitive)
let testString = #"android avantgo blackberry bolt boost cricket docomo hiptop iemobile ipad ipod iphone kitkat mini mobi palm smartphone windows phone symbian up.browser up.link tablet pc tablet browser hp-tablet sony tablet rim tablet webos windows ce wos"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression