import Foundation
let pattern = #"[78]( --[(][)]*[0-9]{10})"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
'84951234567', '+74951234567', '8-495-1-234-567',
' 8 (8122) 56-56-56', '8-911-1234567', '8 (911) 12 345 67',
'8-911 12 345 67', '8 (911) - 123 - 45 - 67', '+ 7 999 123 4567',
'8 ( 999 ) 1234567', '8 999 123 4567'
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression