re = /(.*) (\d{1,19}) missing data lines in iteration/m
str = '[2022-05-01 00:00:00] [Thread-1] ERROR MyLoggerName - Iteration #0. [123456, 456789] - 2 missing data lines in iteration
[2022-05-01 00:01:00] [Thread-1] ERROR MyLoggerName - Iteration #1. [234567, 567890] - 951 missing data lines in iteration'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html