re = /^(?!.*(?: |^)(?:\+\d|0)(?:[()-]*\d){6,}(?!\S)).*/m
str = 'abcd1234567
1234567
123-4567
02221234567
0222-1234567
+862221234567
+86-222-123-4567
+86(222)1234567
86-222-1234567
r 1234567 er
e 123-4567 e
ewq 02221234567 qw
2312 0222-1234567 232
we +862221234567 23
231 +86-222-123-4567 ewe
,,,, +86(222)1234567 sss
ff 86-222-1234567 dd
Some string here with no phone number
a number with 7 and more digits is input
and it starts with 0 or + symbols
and could contain optional symbols "-", "(" and ")"
also enforce whitespace boundaries'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html