import Foundation
let pattern = #"(\S+(?: \S+)*): *(\S+(?: \S+)*)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
OK
AT!GSTATUS?
!GSTATUS:
Current Time: 2420 Temperature: 30
Reset Counter: 1 Mode: ONLINE
System mode: LTE PS state: Attached
LTE band: B30 LTE bw: 10 MHz
LTE Rx chan: 1234 LTE Tx chan: 12345
LTE CA state: NOT ASSIGNED
EMM state: Registered Normal Service
RRC state: RRC Idle
IMS reg state: No Srv
PCC RxM RSSI: -74 RSRP (dBm): -103
PCC RxD RSSI: -74 RSRP (dBm): -104
Tx Power: 0 TAC: 123A (1234)
RSRQ (dB): -12.4 Cell ID: 1234AB56 (12345678)
SINR (dB): 9.4
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression