re = /\b\d{4}(?: \d{4}){3}\b/m
str = ' 2131 2312 1231 3675 4397 3868 0
12332312231231233675 4532 232345 55 345235
2131 2312 1231 3675 '
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html