import Foundation
let pattern = #"^(([a-zA-Z]{2}-?\d{2}-?\d{2})|(\d{2}-?\d{2}-?[a-zA-Z]{2})|(\d{2}-?[a-zA-Z]{2}-?\d{2})|([a-zA-Z]{2}-?\d{2}-?[a-zA-Z]{2})|([a-zA-Z]{2}-?[a-zA-Z]{2}-?\d{2})|(\d{2}-?[a-zA-Z]{2}-?[a-zA-Z]{2})|(\d{2}-?[a-zA-Z]{3}-?\d{1})|(\d{1}-?[a-zA-Z]{3}-?\d{2})|([a-zA-Z]{2}-?\d{3}-?[a-zA-Z]{1})|([a-zA-Z]{1}-?\d{3}-?[a-zA-Z]{2})|([a-zA-Z]{3}-?\d{2}-?[a-zA-Z]{1})|([a-zA-Z]{1}-?\d{2}-?[a-zA-Z]{3})|(\d{1}-?[a-zA-Z]{2}-?\d{3})|(\d{3}-?[a-zA-Z]{2}-?\d{1}))$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
xx-99-99
99-99-xx
99-xx-99
xx-99-xx
xx-xx-99
99-xx-xx
99-xxx-9
9-xxx-99
xx-999-x
x-999-xx
xxx-99-x
x-99-xxx
9-xx-999
999-xx-9
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression