re = /\b(20)\d{2}(0[1-9]|1[0-2])(0[1-9]|[12][0-9]|3[01])\d{6}_(.*)\b/m
str = '20240117130800_works
20250801144000_works
202405231637_missing_two_time_values
20251301144000_invalid_month
20251232144000_invalid_day
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html