import Foundation
let pattern = #"\(?\d{3}\)? {0,2}[-.]? {0,2}\d{3} {0,2}[-.]? {0,2}\d{4}"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
555-555-5555
(555)555-5555
(555) 555-5555
555 -555-5555
(555)555- 5555
(555) 555 -5555
555.555-5555
555.555.5555
5555555555
555-555.5555
(555)5555555
(555).555.5555
(555)-555-5555
(555555-5555
555)-555-5555
555555-5555
555 5555555
555 555 5555
555 - 555 - 5555
555555 . 5555
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression