import Foundation
let pattern = #"(?:A|B|C|D|E|1\)|2\)|3\)|4\)|5\)){0,1}(?:\:|\.|\ ){0,1}[^0-9]{0,2}((?:[\d]{1,2}[\s|\+]{1}){0,4}[\d]{1,2})[\s]{0,1}\*[\s]{0,1}((?:[\d]{1,2}\+[\s]{0,2}){0,98}[\d]{1,2})(?![\+|\-|\d])[\s]{1,3}((?:[\d]{1,2}\+){0,98}[\d]{1,2})"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"""
07 12 21 23 24*01+07+
03+05+08+10+11+13+18+
19+26+28+29+30+31+32
03+04+07+08+09+12
销 轡 时 间 ： 12 ． ． 14 07 ： ： 15 金 额 ： 28 元
A.34+13+13+13+15+35+98-12+12+12
1aaa -foosdsdsdTom Thumb
02+13+13+13+15*05+89-89+12
5s-90
1)红球： 8 10 11 18 20 24 29
23 34
藍球： 5 15
B. 红复 ： 99 10 11 18 20 24 29
藍复 ： 55 15
倍 数 ： 1
A.91 12 23 01 12 23 - 12 (1)
***01 12 23 9 12 23+88 (10)
3.01 12 23 9 55 23+ 88 (10)
E:01 12 23 01 12 8 - 12 x999
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression