re = /(?:\D|^)(?!2016\b)(\d{3,})/m
str = '123 Employee ID DF856, Year 2016, Department Finance, Team 2, Location 112'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html