re = /\b(\d+\/\d+\/\d+)\b/m
str = '0 03/25/93 Total time of visit (in minutes):\\n
1 6/18/85 Primary Care Doctor:\\n
2 sshe plans to move as of 7/8/71 In-Home Servic...
3 7 on 9/27/75 Audit C Score Current:\\n
4 2/6/96 sleep studyPain Treatment Pain Level (N...
5 .Per 7/06/79 Movement D/O note:\\n
6 4, 5/18/78 Patient\'s thoughts about current su...
7 10/24/89 CPT Code: 90801 - Psychiatric Diagnos...
8 3/7/86 SOS-10 Total Score:\\n
9 (4/10/71)Score-1Audit C Score Current:\\n
10 (5/11/85) Crt-1.96, BUN-26; AST/ALT-16/22; WBC...
11 4/09/75 SOS-10 Total Score:\\n
12 8/01/98 Communication with referring physician...
13 1/26/72 Communication with referring physician...
14 5/24/1990 CPT Code: 90792: With medical servic...
15 1/25/2011 CPT Code: 90792: With medical servic...
16 4/12/82 Total time of visit (in minutes):\\n
17 1; 10/13/1976 Audit C Score, Highest/Date:\\n'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html