import Foundation
let pattern = #"((?:\d{2}:)?\d{2}:\d{2}\.\d{3})[^\n]+level[^\d]+(\d{3})"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
00:00.300 ID:4 zzzzzzzzzzz
00:02.155 ID:4 aaaaaaaaaaaaa
00:04.662 ID:4 dsadasd
**00:32.283** ID:4 level **790**
00:32.155 ID:4 Sfghgfs
00:32.200 ID:4 Tsdfsdfdfsff
**00:32.205** ID:4 level **640**
00:32.206 ID:4 Sadssd
00:32.208 ID:4 asdasgsfgsgsagsa
00:32.210 ID:4 adasgx
00:32.212 ID:4 Masddasdas.
**01:40:40.698** ID:4 level **500**
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression