import Foundation
let pattern = #"[A-HJ-NP-TV-Z]{2}[\s-]{0,1}[0-9]{3}[\s-]{0,1}[A-HJ-NP-TV-Z]{2}|[0-9]{2,4}[\s-]{0,1}[A-Z]{1,3}[\s-]{0,1}[0-9]{2}"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = ###"""
## OLD FROMAT (complete) ##
3123 AA 11
3123-AA-11
3123AA11
8987 VG 33
8987VG33
## OLD FORMAT (with few characters) ##
31 F 11
## NEW FORMAT ##
AA 123 BB
AA-222-BB
DD345EE
AO 123 BB // O is excluded
AI-123-BB // I is excluded
AU123BB // U is exclided
AZ 123 BI
AZ-123-BU
AZ123BO
"""###
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression