re = /^0((13|2[2-4]|3|4[05-8]|5[05]|6[24-689]|8[2468]|9[235-7])\d{7}|1[0125]\d{8})$/m
str = '0237802486
0237794824
0225292828
0222803359
0244672263
0683362700
0927922556
01020304050
01177777777
01234567890
01018028445
01015030111'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html