const regex = /^((?! # This and the final line allow invert the regex condition
PA(?:
\*(?:N\s*\d+\s*\.\s*\d+\s*\*ADP)? # match the asterisk cases
| \#\s*N\s*\d+\s* # or the hash cases
(?:[\.,-]\s*\d+\s*){0,5}
\#ADP\s*(?:\d|\#PUSH)
| \#NUAL,AZ,AN\#FOP\d # or the 'UAL,AZ,AN' literal
)
).)*$/gm;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('^((?! # This and the final line allow invert the regex condition
PA(?:
\\*(?:N\\s*\\d+\\s*\\.\\s*\\d+\\s*\\*ADP)? # match the asterisk cases
| \\#\\s*N\\s*\\d+\\s* # or the hash cases
(?:[\\.,-]\\s*\\d+\\s*){0,5}
\\#ADP\\s*(?:\\d|\\#PUSH)
| \\#NUAL,AZ,AN\\#FOP\\d # or the \'UAL,AZ,AN\' literal
)
).)*$', 'gm')
const str = `# OP's samples
PA#N1.1#ADP1
PA#N1.1,1.2#ADP1,2
PA#N1#ADP4
PA#N1,2#ADP4
PA#N1,2.1,3#ADP1
PA#N1.1-3#ADP1
PA#N1.1- 3.2#ADP1,2
PA#NUAL,AZ,AN#FOP123
PA#N1.1-2.1,3.1#ADP#PUSH
PA*N1.1*ADP
PA*
# The same with some spaces adde here and there
PA# N 1.1 #ADP1
PA#N 1.1,1.2#ADP1,2
PA#N1#ADP4
PA#N1,2 #ADP4
PA#N1,2. 1,3#ADP1
PA#N1.1-3#ADP1
PA#N1.1- 3.2#ADP1,2
PA#NUAL,AZ,AN#FOP123
PA#N1.1-2 . 1 , 3 . 1 #ADP#PUSH
PA*N1 .1*ADP
PA#N1.1...#5#SOME TEXT
`;
// Reset `lastIndex` if this regex is defined globally
// regex.lastIndex = 0;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions