re = /^(?:(?:19|20)\d\d([-\/.])(?:0?[1-9]|1[012])\1(?:0?[1-9]|[12][0-9]|3[01])|(?:0?[1-9]|[12][0-9]|3[01])([-\/.])(?:0?[1-9]|1[012])\2(?:19|20)(?:\d\d)?)$/m
str = '31-1-20
1-12-1990
1900/08/23
'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html