re = /((0[1-9]|[12]\d|3[01]])-(0[1-9]|1[0-2])-[12]\d{3}(?:\s[mf])?)/m
str = ': 02-03-1980 m or 02-03-1980 f but'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html