import Foundation
let pattern = #"^(?:(?:(?:(?:(?:(?:0[13578])|(?:1[02]))\/(?:(?:0[1-9])|(?:[1-2][0-9])|(?:3[01])))|(?:(?:(?:0[469])|11)\/(?:(?:0[1-9])|(?:[1-2][0-9])|30))|(?:02\/(?:(?:0[1-9])|(?:[1-2][0-9]))))\/\d{2}(?:(?:[02468][048])|(?:[13579][26])))|(?:(?:(?:(?:(?:0[13578])|(?:1[02]))\/(?:(?:0[1-9])|(?:[1-2][0-9])|(?:3[01])))|(?:(?:(?:0[469])|(?:11))\/(?:(?:0[1-9])|(?:[1-2][0-9])|(?:30)))|(?:02\/(?:(?:0[1-9])|(?:1[0-9])|(?:2[0-8]))))\/\d{2}(?:(?:[02468][1235679])|(?:[13579][01345789]))))(?:\s(?:(?:(?:0[1-9])|(?:1[0-2]))\:(?:[0-5][0-9])(?:\:(?:[0-5][0-9])\s))(?:AM|PM|am|pm))?$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
12/12/2012
12/12/2012 05:05:59 am
02/29/2012
02/29/2010
02/28/2010
12/31/2012 11:59:55 pm
25/12/2019 05:00:00 pm
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression