import Foundation
let pattern = #"(\+?(?:(84|0))(\s?[\-\u2010\u2011\u2012\u2013\u2014\u2015]?\s?)[357-9]\d{6}(?:\d{2}(?:\d{1})?)?)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
1234567
76543211234
123456789
12345778
1234567890
+8412345678
84123456789
8412345
84123456
+1234567
+84
0123456
+84356763987
5123456
31234567
712345678
9123456789
+84-5123456
+84 5123456
05123456
0-5123456
+84 - 5123456
843378262
84337671542
84575516147
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression