import Foundation
let pattern = #"(?<=\<OBJ_CODE\>).*(?=\<\/OBJ_CODE\>)"#
let regex = try! NSRegularExpression(pattern: pattern, options: .caseInsensitive)
let testString = ##"""
<OBJ_CODE>(01)08699543091808(21)1000153104910(91)9185(92)92JEIF840$JDFDSA!L;ASDJASDMASDLKFJANE;ASDFLHJA(17)251231</OBJ_CODE>
</item>
<item>
<OBJ_CODE>(01)08699543091808(21)1000181393500(91)9185(92)92546KLJDF(G9)AALDFJ^KLJBN346#NDSFL%LKJADADNRI(17)251231</OBJ_CODE>
</item>
<item>
<OBJ_CODE>(01)08699543091808(21)1000121219920(91)9185(92)92489345MDFSLK8945893,5HJDSFKL3$LKJSDGFALKJDFG(17)251231</OBJ_CODE>
</item>
<item>
<OBJ_CODE>(01)08699543091808(21)1000164832760(91)9185(92)92DSAFL48904!KASDFG^;LKJASDF%ASDFLKJNASL34JD34(17)251231</OBJ_CODE>
</item>
<item>
<OBJ_CODE>(01)08699543091808(21)1000124140420(91)9185(92)92%LSDAFASDF9084A;LKLJ!;LK(23)4ASDF724LK$LJ$;L(17)251231</OBJ_CODE>
</item>
<item>
<OBJ_CODE>(01)08699543091808(21)1000161028910(91)9185(92)92834HASKLJHSDA$KJH%;LHJL(DF)^ASDFKLJDSFLKW!;L(17)251231</OBJ_CODE>
</item>
<item>
<OBJ_CODE>(01)08699543091808(21)1000135787250(91)9185(92)9290KLKLNAB%KLJAKLJ^7DSFKLJASDG234KLJSD#4LHASD(17)251231</OBJ_CODE>
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression