import Foundation
let pattern = #"\d+(?:\.\d+)?\s+EXP\s+New\strial\s\([^)]*\):\s+{[^}]+}"#
let regex = try! NSRegularExpression(pattern: pattern)
let testString = #"483.3731 EXP New trial (rep=0, index=1): {u'selectPlayer': 1, u'neutralStim4': u'PSYCHOLOGIST', u'neutralStim2': u'PONG', u'neutralStim': u'YEN', u'positiveStim': u'PEACEFUL', u'neutralStim3': u'DASH', u'positiveStim3': u'HAPPY', u'positiveStim2': u'HONORABLE', u'negativeStim': u'BETRAYAL', u'negativeStim4': u'GUNPOINT', u'negativeStim3': u'JEALOUS', u'negativeStim2': u'MISTRUST', u'positiveStim4': u'AWESOME'}"#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression