import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Example {
public static void main(String[] args) {
final String regex = "([\"']).*\\1(?![^\\s])";
final String string = "\"a'b\"\n"
+ "\"ab\"\n"
+ "'ffg' \"hhh\"\n"
+ "\"\"\n"
+ "''\n"
+ "\"'\"\n"
+ "'acd\" 'gf\n"
+ "\"Don't forget the @\"";
final Pattern pattern = Pattern.compile(regex);
final Matcher matcher = pattern.matcher(string);
while (matcher.find()) {
System.out.println("Full match: " + matcher.group(0));
for (int i = 1; i <= matcher.groupCount(); i++) {
System.out.println("Group " + i + ": " + matcher.group(i));
}
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Java, please visit: https://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html