# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"(((\+49\ ))|(0))\d{3,4}\ (\d{7}|\d{6}(\-\d{2})?)"
test_str = ("// valid\n"
"//Landline\n"
"0221 999985\n"
"0221 999985-80\n"
"// Mobile\n"
"01578 1234567\n"
"// International\n"
"+49 221 999985\n"
"+49 221 999985-60\n"
"+49 1578 1234567\n\n"
"// invalid\n"
"(06442) 3933023\n"
"(02852) 5996-0\n"
"(042) 1818 87 9919\n"
"06442 / 3893023\n"
"06442 / 38 93 02 3\n"
"06442/3839023\n"
"042/ 88 17 890 0\n"
"+49 221 549144 – 79\n"
"+49 221 - 542194 79\n"
"+49 (221) - 542944 79\n"
"0 52 22 - 9 50 93 10\n"
"+49(0)121-79536 - 77\n"
"+49(0)2221-39938-113\n"
"+49 (0) 1739 906-44\n"
"+49 (173) 1799 806-44\n"
"0173173990644\n"
"+4922154219479\n"
"0214154914479\n"
"02141 54 91 44 79\n"
"01517953677\n"
"+491517953677\n"
"015777953677\n"
"02162 - 54 91 44 79\n"
"(02162) 54 91 44 79\n"
"saddsadasdasd\n"
"asdasd\n"
"asdasd asdasd asd\n"
"asdasd\n"
"kjn asohas asdoiasd\n"
"23434 234 234 23\n"
"323\n"
"23434 234----234\n"
"///// ----\n"
"// id8834 3493934 //\n")
subst = ""
# You can manually specify the number of replacements by changing the 4th argument
result = re.sub(regex, subst, test_str, 0)
if result:
print (result)
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html