re = /(?<=\d{6})(\d+)(?=\d{4})/
str = '4548812049400004
5229782641993099
345678000000007
6362970000457013'
subst = 'X'
result = str.gsub(re, subst)
# Print the result of the substitution
puts result
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html