re = /img.*?title="([^"]+)"\s*src="([^"]+)"/
str = '<img alt="大气超级品牌日活动宣传海报" title="大气超级品牌日活动宣传海报" src="http://pic.qiantucdn.com/58pic/26/32/41/49258PICQdJ.jpg!qt226" width="226" height="546" /> 请问只取title和src 应该怎么写<img alt="大气超级品牌日活动宣传海报" title="大气超级品牌日活动宣传海报" src="http://pic.qiantucdn.com/58pic/26/32/41/49258PICQdJ.jpg!qt226" width="226" height="546" /> 请问只取title和src 应该怎么写<img alt="大气超级品牌日活动宣传海报" title="大气超级品牌日活动宣传海报" src="http://pic.qiantucdn.com/58pic/26/32/41/49258PICQdJ.jpg!qt226" width="226" height="546" /> 请问只取title和src 应该怎么写<img alt="大气超级品牌日活动宣传海报" title="大气超级品牌日活动宣传海报" src="http://pic.qiantucdn.com/58pic/26/32/41/49258PICQdJ.jpg!qt226" width="226" height="546" /> 请问只取title和src 应该怎么写<img alt="大气超级品牌日活动宣传海报" title="大气超级品牌日活动宣传海报" src="http://pic.qiantucdn.com/58pic/26/32/41/49258PICQdJ.jpg!qt226" width="226" height="546" /> 请问只取title和src 应该怎么写<img alt="大气超级品牌日活动宣传海报" title="大气超级品牌日活动宣传海报" src="http://pic.qiantucdn.com/58pic/26/32/41/49258PICQdJ.jpg!qt226" width="226" height="546" /> 请问只取title和src 应该怎么写'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html