using System;
using System.Text.RegularExpressions;
public class Example
{
public static void Main()
{
string pattern = @"^(?!^[0-9])(?![0-9][AZ])(?![AZ0-9*]*\*\*)(?![AZ0-9*]*\*[AZ])((?=[AZ0-9]{6})|(?=[AZ0-9*]*\*))(?![AZ0-9*]*[0-9][A-Z])[AZ0-9*]{1,6}$";
string input = @"^(?![0-9])(?![0-9][AZ])(?![AZ0-9*]*\*\*)(?![AZ0-9*]*\*[AZ0])(?=[AZ0-9*]*\*)(?![AZ0-9*]*[0-9][A-Z])[AZ0-9*]{1,6}$
Broken down:
^(?![0-9])
(?![0-9][AZ])
(?![AZ0-9*]*\*\*)
(?![AZ0-9*]*\*[AZ0])
(?=[AZ0-9*]*\*)
(?![AZ0-9*]*[0-9][A-Z])
[AZ0-9*]{1,6}$
Check these for patterns
Following would be valid
*
*1
*1*
*12345
A*
A*2
A*2*
A1*3
A1*3*
A12*4
A*2
A*23
A*234
A*2345
A12*45
A1234*
A*2345
A12*4*
A*23*5
A123*5
*12345
*1234*
*1*3*5
*12*4*
*1*3*5
*123*5
A12345
Examples of invalid entries: <Any ** entry> - <Any * A-Z character> - <Any value longer than 6>
A1
A12
A123
A1234
*A1234
B*
B1*
BA*45
B*2345
**
*1A
*1A1*
*A2345
*123456
1234*
A
**12
*1**
*1*3**
*12**
*1*3*56
*123**
*12*45*
A*23456";
RegexOptions options = RegexOptions.Multiline;
foreach (Match m in Regex.Matches(input, pattern, options))
{
Console.WriteLine("'{0}' found at index {1}.", m.Value, m.Index);
}
}
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for C#, please visit: https://msdn.microsoft.com/en-us/library/system.text.regularexpressions.regex(v=vs.110).aspx