re = /^((0[1-9]|[12]\d|3[01])-(0[1-9]|1[0-2])-[12]\d{3})$/m
str = '22-10-2000
10-22-2000
2-10-2000
22-1-2000
2000-10-22
02-01-2000
00-10-2000
22-00-2000
22-10-0010
22-10-7000
// You can show origina post on albertcolom.com/blog'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html