import re
regex = re.compile(r"^(?:\((?P<imp>[A-Z])\)\ )?(?P<dued>(?:2[0-1][0-9]{2}\-(?:0[0-9]|1[0-2])\-(?:[0-2][0-9]|3[0-1]))|\?)\ (?:\+(?P<proname>[a-zA-Z0-9]+)(?:\#(?P<pronum>[0-9]+))?\ )?(?:\$(?P<startd>2[0-1][0-9]{2}\-(?:0[0-9]|1[0-2])\-(?:[0-2][0-9]|3[0-1]))(?:\^(?P<repeat>\d*(?:D|W|M|Y)(?:\,\d*(?:D|W|M|Y)+)*))?\ )?(?P<todo>.+?(?=(?:\ (?:\@|\&))|$))(?P<contexts>(?:\ \@\S+)*)(?P<tags>(?:\ \&\S+)*)", flags=re.MULTILINE)
test_str = ("(A) 2016-10-23 +projectB $2016-10-03 to be completed as soon as possible @context_bar\n"
"(A) 2016-11-01 +projectA $2016-09-25 job to complete @context @context_two\n"
"(B) ? +houseworks $2016-10-04^2D,W lavoro importante &TAG_FOO &TAG_BAR\n"
"2016-12-15 +projectA#2 $2016-09-25 second job related to the same project @another_context\n"
"? +houseworks $2016-10-02^3D altro lavoro di casa @context_bar &TAG\n"
"? +projectA#3 $2016-09-25 third job of the same project @foo_context &WAIT\n"
"? +projectA#4 $2016-09-25 fourth job, needs third to be completed first\n"
"2016-11-23 $2015-06-23^4Y another job without project @context_foo @context_bar &TAG_A &TAG_B\n"
"? minimal job like email fra@me.com")
matches = regex.finditer(test_str)
for match_num, match in enumerate(matches, start=1):
print(f"Match {match_num} was found at {match.start()}-{match.end()}: {match.group()}")
for group_num, group in enumerate(match.groups(), start=1):
print(f"Group {group_num} found at {match.start(group_num)}-{match.end(group_num)}: {group}")
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html