import Foundation
let pattern = #"^127.0.0.1|168\.192\.([0-9]|[1-9][0-9]|1[0-1][0-9])\.([1-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
168.192.2.100
168.192.109.1
168.192.0.1
168.192.0.25
168.192.255.2
168.192.110.1
168.192.100.1
168.192.210.1
168.192.256.4
168.192.0.255
168.192.200.255
168.192.19.
168.192.34.10
168.192.100.10
168.192.51.200
168.192.81.9
168.192.111.133
168.192.112.133
168.192.111.256
168.192.111.216
168.192.111.236
168.192.110.1
168.192.111.100
168.192.110.200
168.192.110.300
168.192.110.1
168.192.110.1
168.192.1.9
168.192.100.0
268.
2.
168.1.
1.^168\.192\.([1-9]|[1-9][0-9]|[1-2][0-4][0-9]|25[0-5])\.([1-9]|[1-9][0-9]|[1-2][0-4][0-9]|25[0-5])$
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression