re = /^(?:(?:\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.){3}(?:\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])$/m
str = '0.0.0.0
1.1.1.1
9.9.9.9
10.10.10.10
99.99.99.99
100.100.100.100
199.199.199.199
200.200.200.200
255.255.255.255
256.256.256.256
1.1.1.1.1
foo.bar.baz.qux'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html