re = /(?<=")[23]{1,7}(?=")/
str = '"3"sca"""co"1"str"0"ctor""r"3"t"0"r"1""locat"5"o"133""0"27""754a49b393c2a0"33"b97"332"cb7"3"c3c07"2""co"1"str"0"ct"233223322"or""r"3"t"0"'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html