re = /^(\.+)(\d+(,\d*)?\.\d{2})$/m
str = '00.0
123
123.
123.123
.13
.123.
123,0.00
12,12.
.12,12.00
.1.
..1.
...12.
...18724.34
.18,724.34'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html