re = /(?<userid>[^\"]+@[^\"]+)/m
str = '01022703
021216
07602381
"1206931120@GSA.GOV"
177
177670
1969412
232789'
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html