const regex = /^(?=(?!\d+\D0?2\D29)|(?=\d{2}(?:04|08|[13579][26]|[2468][048]|1[26]00|2000)\D0?2\D29))(1\d{3}|20(?:0\d|1[0-4]))[\/.]((?:0?[13578]|10|12)[\/.](?:[0-2]?\d|3[0-1])|(?:0?[469]|11)[\/.](?:[0-2]?\d|30)|0?2[\/.](?:[0-1]?\d|2[0-9]))$/gm;
// Alternative syntax using RegExp constructor
// const regex = new RegExp('^(?=(?!\\d+\\D0?2\\D29)|(?=\\d{2}(?:04|08|[13579][26]|[2468][048]|1[26]00|2000)\\D0?2\\D29))(1\\d{3}|20(?:0\\d|1[0-4]))[\\\/.]((?:0?[13578]|10|12)[\\\/.](?:[0-2]?\\d|3[0-1])|(?:0?[469]|11)[\\\/.](?:[0-2]?\\d|30)|0?2[\\\/.](?:[0-1]?\\d|2[0-9]))$', 'gm')
const str = `2014/12/31
1937/4/17
1066/1/4
1066/2/28
2014/1/1
2012/02/29
1066/1/4444
1066/2/29
1065/2/29
2014/14/1
2014/02/29
`;
// Reset `lastIndex` if this regex is defined globally
// regex.lastIndex = 0;
let m;
while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
regex.lastIndex++;
}
// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
console.log(`Found match, group ${groupIndex}: ${match}`);
});
}
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for JavaScript, please visit: https://developer.mozilla.org/en/docs/Web/JavaScript/Guide/Regular_Expressions