$re = '/(<img.*src=)["\']https:\/\/(.*)["\']/m';
$str = '<p><img class="alignnone wp-image-36109 size-full" src="https://onhax.net/wp-content/uploads/2014/10/WjhzQlNRaDJrYUUx_o_using-freedom-for-unlimited-in-app-purchases-android-.jpg" alt="WjhzQlNRaDJrYUUx_o_using-freedom-for-unlimited-in-app-purchases-android-" width="480" height="360"/></p>
<img class="alignnone size-full wp-image-126019" src="https://i0.wp.com/onhax.net/wp-content/uploads/2016/03/sd.png?resize=300%2C300" alt="" data-recalc-dims="1"/>
<img class="alignnone size-full wp-image-126019" src="https://onhax.net/wp-content/uploads/2016/03/sd.png?resize=300%2C300" alt="" data-recalc-dims="1"/>';
$subst = "\1\"http://example.com/\2\"";
$result = preg_replace($re, $subst, $str, 1);
echo "The result of the substitution is ".$result;
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for PHP, please visit: http://php.net/manual/en/ref.pcre.php