import Foundation
let pattern = #"^(?P<status_codes>(i|s|x|S|d|h|\*|\>|\s)+) *(?P<prefix>(?P<ip>[0-9\.\:\[\]]+)\/(?P<mask>\d+))? +(?P<next_hop>\S+) +(?P<number>[\d\.\s\{\}]+)(?: *(?P<origin_codes>(i|e|\?)))?$"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
s>i2001:718::2:99/128 195.113.156.4 0 100 0 i
s i 195.113.156.4 0 100 0 i
s>i2001:718::2:101/128
10.2.8.1 0 100 0 i
s i 10.2.8.1 0 100 0 i
s>i2001:718::2:116/128
195.113.156.9 1000 205 0 65086 i
s i 195.113.156.9 1000 205 0 65086 i
s i 2001:718:0:600:0:1a:1a:11
1000 110 0 65086 i
s>i2001:718:180a::/48 10.2.7.1 11 100 0 65091 ?
s i 10.2.7.1 11 100 0 65091 ?
s>i2001:718:180b::/48 10.2.7.1 18 100 0 65091 ?
s i 10.2.7.1 18 100 0 65091 ?
s>i2001:718:180c::/48 10.2.7.1 11 100 0 65091 ?
s i 10.2.7.1 11 100 0 65091 ?
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression