Regular Expressions 101

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An explanation of your regex will be automatically generated as you type.
Detailed match information will be displayed here automatically.
  • All Tokens
  • Common Tokens
  • General Tokens
  • Anchors
  • Meta Sequences
  • Quantifiers
  • Group Constructs
  • Character Classes
  • Flags/Modifiers
  • Substitution
  • A single character of: a, b or c
    [abc]
  • A character except: a, b or c
    [^abc]
  • A character in the range: a-z
    [a-z]
  • A character not in the range: a-z
    [^a-z]
  • A character in the range: a-z or A-Z
    [a-zA-Z]
  • Any single character
    .
  • Alternate - match either a or b
    a|b
  • Any whitespace character
    \s
  • Any non-whitespace character
    \S
  • Any digit
    \d
  • Any non-digit
    \D
  • Any word character
    \w
  • Any non-word character
    \W
  • Non-capturing group
    (?:...)
  • Capturing group
    (...)
  • Zero or one of a
    a?
  • Zero or more of a
    a*
  • One or more of a
    a+
  • Exactly 3 of a
    a{3}
  • 3 or more of a
    a{3,}
  • Between 3 and 6 of a
    a{3,6}
  • Start of string
    ^
  • End of string
    $
  • A word boundary
    \b
  • Non-word boundary
    \B

Regular Expression
Processing...

Test String

Substitution
Processing...

Code Generator

Language

Generated Code

import re regex = re.compile(r"(ENERGIA ELETRICA CONSUMO(.|\n)*?%)", flags=re.MULTILINE) test_str = ("\"5758 6128 370 kWh 1 370 kWh 11,93 kWh 12/07/2019 01/08/2019\n" "Mês kWh Dt.Pgto. Valor\n" "06/2019 355 17/06/2019 343,79\n" "NOTA FISCAL/CONTA DE ENERGIA ELÉTRICA N° 085.976.711 - SÉRIE B\n" "Emitida em 03/07/2019\n" "05/2019 332 14/05/2019 306,84\n" "Produto Valor Valor Base Aliq.\n" "04/2019 415 29/05/2019 378,67\n" "Descrição Un. Consumo Unitário Total Cálc. ICMS\n" "03/2019 308 14/05/2019 269,81\n" "ENERGIA ELETRICA CONSUMO kWh 370 0,787324 291,31 291,31 29,00%\n" "02/2019 347 26/04/2019 305,09\n" "ENERGIA CONS. B.AMARELA kWh 0,54 0,54 29,00%\n" "01/2019 341 11/03/2019 324,39\n" "12/2018 301 26/12/2018 287,83\"") subst = "" result = regex.sub(subst, test_str) if result: print(result)

Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Python, please visit: https://docs.python.org/3/library/re.html