re = /(?!LogL=)\d/
str = ' 7 LogL=-3695.47 S2= 9.0808 1891 df 2.263 0.2565
9 LogL= 2456.30 S2= 1.2789 1785 df 1.244 0.1354 '
# Print the match result
str.scan(re) do |match|
puts match.to_s
end
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Ruby, please visit: http://ruby-doc.org/core-2.2.0/Regexp.html