import Foundation
let pattern = #"\w{3}\s\d{2}\s\d{2}:\d{2}:\d{2}\s\w+\s\w+\[\d+\]:\squery\[\w+\]\s([\da-z\.-]+\.[a-z]{2,6})\s\w+\s(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
Jul 30 00:00:41 rpi dnsmasq[571]: query[A] officescan.corp.arcon.com.br from 192.168.5.187
Jul 30 00:00:43 rpi dnsmasq[571]: query[A] teams.events.data.microsoft.com from 192.168.5.187
Jul 30 00:00:43 rpi dnsmasq[571]: forwarded teams.events.data.microsoft.com to 1.0.0.1
Jul 30 00:00:43 rpi dnsmasq[571]: forwarded teams.events.data.microsoft.com to 1.1.1.1
Jul 30 00:00:43 rpi dnsmasq[571]: reply teams.events.data.microsoft.com is <CNAME>
Jul 30 00:00:43 rpi dnsmasq[571]: reply teams-events-data.trafficmanager.net is <CNAME>
Jul 30 00:00:43 rpi dnsmasq[571]: reply skypedataprdcolweu02.cloudapp.net is 52.114.74.43
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression