import Foundation
let pattern = #"(?:^|(?<=[\D;a-zA-Z(),.:;?!"'`>]))(?!000|666|9)(?<![Oo][Rr][Dd][Ee][Rr].)(?<![Oo][Rr][Dd][Ee][Rr]..)(?<![Oo][Rr][Dd][Ee][Rr]...)(?<![Oo][Rr][Dd][Ee][Rr].[Nn][Uu][Mm][Bb][Ee][Rr].)(?<![Oo][Rr][Dd][Ee][Rr].[Nn][Uu][Mm][Bb][Ee][Rr]..)(?<![Oo][Rr][Dd][Ee][Rr].[Nn][Uu][Mm][Bb][Ee][Rr]...)(?<![Xx])\d{3}[ -.=\n\r]{0,10}(?!00)\d{2}[ -.=\n\r]{0,10}(?!0000)\d{4}(?:$|(?=[\Da-zA-Z(),.:;?!"'`<= ]))"#
let regex = try! NSRegularExpression(pattern: pattern, options: [.anchorsMatchLines, .caseInsensitive])
let testString = ##"""
Order numbers should not get detected if 'X or x' precedes the number. so this is working fine.
x123456789
X123456789
x123-456-789
X123-456-789
123-456-789
Need to modify the regex pattern to get the match for the list of ordernumbers written like below...along with the word (order number) should be case insensitive.
ordernumber123-456-789
order number123-456789
order number 123456789
123-456789
123456789
ordernumber-123456787
ordernumber - 123456789
ordernumber #123456789
ordernumber *anysplcharacter*123456789
"""##
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression