import Foundation
let pattern = #"^C\w*(?:-\d+)?(?:-\d+)?\W*111\b"#
let regex = try! NSRegularExpression(pattern: pattern, options: .anchorsMatchLines)
let testString = #"""
V0EQ21309-128 1 1001600535.99N0023642.63E 478409.56662024.7 107.91520748348
S0EQ21309-128 11 1001600532.60N0023645.31E 478450.26661919.6 0.01520748348
T0EQ21309-128 1 1 1001600452.10N0023713.63E 478880.66660664.0 0.01520748348
T0EQ21309-128 1 2 1001600452.35N0023715.00E 478901.96660671.8 0.01520748348
C0EQ21309-128 111 1001600532.07N0023645.24E 478449.06661903.2 0.01520748348
C0EQ21309-128 113 1001600532.22N0023646.01E 478461.06661907.6 0.01520748348
C012PA105 111 1003660607.77N0080416.09E 458009.87331794.0 365.21171920443
C012PA105 113 1003660607.96N0080415.12E 457997.77331800.2 365.21171920443
C012PA105 122 1004660607.65N0080415.58E 458003.57331790.5 365.31171920472
C012PA105 124 1004660607.84N0080414.62E 457991.47331796.6 365.31171920472
"""#
let stringRange = NSRange(location: 0, length: testString.utf16.count)
let matches = regex.matches(in: testString, range: stringRange)
var result: [[String]] = []
for match in matches {
var groups: [String] = []
for rangeIndex in 1 ..< match.numberOfRanges {
let nsRange = match.range(at: rangeIndex)
guard !NSEqualRanges(nsRange, NSMakeRange(NSNotFound, 0)) else { continue }
let string = (testString as NSString).substring(with: nsRange)
groups.append(string)
}
if !groups.isEmpty {
result.append(groups)
}
}
print(result)
Please keep in mind that these code samples are automatically generated and are not guaranteed to work. If you find any syntax errors, feel free to submit a bug report. For a full regex reference for Swift 5.2, please visit: https://developer.apple.com/documentation/foundation/nsregularexpression